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(-3)=2F^2-3F+4
We move all terms to the left:
(-3)-(2F^2-3F+4)=0
We add all the numbers together, and all the variables
-(2F^2-3F+4)-3=0
We get rid of parentheses
-2F^2+3F-4-3=0
We add all the numbers together, and all the variables
-2F^2+3F-7=0
a = -2; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·(-2)·(-7)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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